Example 1
In how many ways can three friends A, B and C stand in a line?
- Start with A first: ABC, ACB.
- Then B first: BAC, BCA.
- Then C first: CAB, CBA.
- That is 3 groups of 2.
Answer: 6 ways
🏅 Olympiad maths · session 3 of 49 · 60 minutes · ⭐ Plus
How many outfits, codes or numbers can you make? Learn to count them without writing every one: list in order, draw a tree, then multiply the choices.
A complete lesson · 60 minutes
Open this page with your learner and work down it, or press Teach this lesson to go through it one step at a time on a big screen. Every section has something to do.
Classes 4 to 7 · ages 9 to 13
Warm-up · think first
6 outfits: red with each of the 3 shorts, and blue with each of the 3 shorts. 2 × 3 = 6. Today you will learn why multiplying works, and how it saves time when there are hundreds of outfits.
Teacher tip: Let them list freely first. Then ask: how can we be sure we did not miss one? That leads to listing in order.
Part 1 of 4 · learn, see, practise
When you list possibilities, fix the first choice and go through every second choice, then move to the next first choice. This stops you missing or repeating any.
Arrangements of things in a line are a good example: write them in alphabetical order.
In how many ways can three friends A, B and C stand in a line?
Answer: 6 ways
Think first: List all the 2-digit numbers you can make from the digits 1, 2 and 5 without repeating a digit.
Start with the warm-up and go as far as you can. The stretch questions are meant to be hard.
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FAQ
If one choice can be made in a ways and the next in b ways, the two together can be made in a × b ways. It extends to any number of steps.
9 × 9 × 8 = 648: 9 choices for the first digit (not 0), then 9, then 8.
When choices happen one after another and you want to see every possibility. It also shows why the multiplication principle works.
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